Relation between Momentum and K.E Question: If Momentum of a body is increased by 20%, what is percentage change in the K.E of the body? a) 40% b) 44% c) 20% d) 10% Answer: 44% Solution: Let the original momentum of the body be P, Then: P=mv Momentum is increased by 20%, so new momentum will be: P' = P + 20%P P' = P + 0.2P = 1.2P K.E = 0.5 mv^2 =0.5 m^2v^2/m (multiply and divide by m) K.E = 0.5 P^2 / m ---------- (i) New K.E = K.E' = 0.5 (P')^2/m = 0.5 (1.2P)^2 / m ...