GIKI Admission Schedule

GIKI Admission Schedule for Under Graduate Programs

GIKI Admission Calender https://www.facebook.com/Etest.Prep
Sr. No	Date	Activity
1	April 26, 2015	Online Submission of Application Form Starts
2	April 27, 2015	Availability of Prospectus
3	June 19, 2015	Online Submission of Admission Form Ends
4	June 19, 2015	Last Date for Payment of Processing Fee
5	June 19, 2015	Last Date for Dispatch of Admission Documents & Processing Fee By Applicants
6	June 22, 2015	Last Date for Receipt of Admission Documents at GIK Institute
7	June 27, 2015	Last Date for Dispatch of Dispatch of Admit Cards From GIK Institute
8	July 5, 2015	Admission Test
9	July 7, 2015	Last Date for Receipt of SAT-2 Scores (Overseas Applicants)
10	July 11, 2015	Admission Test Result Posted on website
11	August 22 - 23, 2015	Induction Ceremony
12	August 24, 2015	Semester Starts

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Registration process for NUST Entrance Test

The registration process for Nust Entrance test is online. An online form is to be filled in order to get registered for the test. Below are the steps of registration. Step 1: Open the admission homepage of Nust: Nust undergraduate admissions Click on New registration button,as shown in the picture below: A new page will open stating some instructions and a form to create login. Step 2: Fill that form and submit. After submission following page will appear. Step 3: Open up your mail box , and check the new emails. There will be an email from Nust UG admissions 2015. If it is not present in inbox, check the spam folder. The email contains a login and a password. Use that to login on admission homepage of NUST. Step 4: Following page will appear once you'll login to your account: Click on Application form, and enter the required data. Enter the correct data as in correct data may lead to cancellation of admission. Once you have filled the complete f

Ampere's Law

Ampere�s Law � If a circular loop is drawn around a current carrying conductor; it will erect a magnetic field � B � around it, then to free space� ?B/� dl = I Where, ? is the integral representation of the total area of magnetic field �B� of the circular loop of current carrying conductor. In case of Straight Wire: Since, �B� (the red dots) is uniform, it behave as a constant value (as amount of current is same in conductor). Now �dl� is a small part of the total circular loop, for which we have to find the value of �B� at that point. Now, as �dl� is small area of the circle, or we can say it�s a derivative of the total area bounded by the circular loop (circumference of the circular loop), so, if we take an integral of �dl� we can have the total area bounded by the circular loop which is 2pr. In case of Solenoid: Here, the solenoid has number of turns �N� and is having a

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Given below is the Comparison of the Statistics of ECAT 2015 with the stats of last few years. It clearly indicates that merit is going to fall this year. It might fall as much as 1% or even more. Marks Interval Number of Candidates ECAT 2011 ECAT 2012 ECAT 2013 ECAT 2014 ECAT 2015 Students with marks 0 or Less than 0 408 235 203 248 63 01 - 50 7813 4734 5423 5421 7465 51 - 100 12222 10435 14389 12748 16370 101 - 150 7304 10563 11978 12591 10434 151 - 200 3131 6670 7063 7004 4446 201 - 250 630 2798 2965 2384 1351 251 - 300 43 667 672 488 255 301 - 400 02 114 86 17 41 Total Number of Candidates 31553 36216 42779 40985 40425 Average Marks 96 118 107 107.5 96 The merit this year is going to be lower than the merit of 2012, 2013 & 2014 but will be higher than the merit of 2011. Credits: SWAMI Mianwalli

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