Skip to main content

Test Session For CMH & FMH


Test Session For CMH & FMH
Fee = Rs 1000 Only

Entrance Test of CMH for the admission year 2015 is scheduled to be conducted on 8th Nov, 2015. There will be 5 portions in the test:
  1. Biology
  2. Chemistry
  3. Physics
  4. English
  5. Intelligence
Total 100 questions will be there from these 5 subjects, 20 from each of these. Total time provided to solve the paper is 2 hours.

Entrance Test of FMH are staring from 2 November, 2015 and they will continue for about a week as these are computerized tests. There will be 5 portions in the test:
  1. Biology - 10 MCQs
  2. Physics - 10 MCQs
  3. Chemistry - 10 MCQs
  4. English - 15 MCQs
  5. General Knowledge - 15 MCQs
Full Books of Fsc are to be covered for Sciences (Bio, Chm, Phy). For English questions will be from synonyms, antonyms, grammar and comprehension.

About the test Session:
In this session we will provide chapter wise tests of Bio, Chm and Phy (all chapters). These will be online tests. When you will solve the test you will be shown the correct answers and the solutions of all the questions. Moreover a guide on how to solve the intelligence questions (For CMH) along with practice questions will also be provided to the registered students. Notes about general knowledge (For FMH) will be provided. Questions from past papers, which we could, will be shared with the students.

How to register?
Open the course page ( link : http://oetp.pk/course/online-test-session-for-cmh-fmh/ ), click on Take This Course option, a form will appear, fill and click on Place The Order. Fee details will be shown to you, you will also receive a receipt via email to your email address. Submit the fee in HBL and send a picture of the paid deposit slip via email to us and your course will be approved.

In case of any issue feel free to contact.

Contact Details:
Cell Number: 03456712289 (Hassan Shahbaz)


Comments

Popular posts from this blog

Registration process for NUST Entrance Test

The registration process for Nust Entrance test is online. An online form is to be filled in order to get registered for the test. Below are the steps of registration.  Step 1:  Open the admission homepage of Nust:  Nust undergraduate admissions   Click on New registration button,as shown in the picture below:                A new page will open stating some instructions and a form to create login.  Step 2:  Fill that form and submit. After submission following page will appear.       Step 3:   Open up your mail box , and check the new emails. There will be an email from Nust UG admissions 2015. If it is not present in inbox, check the spam folder. The email contains a login and a password. Use that to login on admission homepage of NUST. Step 4:   Following page will appear once you'll login to your account: Click on Application form, and enter the required data. Enter the correct data as in correct data may lead to cancellation of admission. Once you have filled the complete f

Ampere's Law

Ampere�s Law � If a circular loop is drawn around a current carrying conductor; it will erect a magnetic field � B � around it, then to free space�                                                              ?B/�  dl = I Where, ? is the integral representation of the total area of magnetic field �B� of the circular loop of current carrying conductor. In case of Straight Wire:                                                    Since, �B� (the red dots) is uniform, it behave as a constant value (as amount of current is same in conductor). Now �dl� is a small part of the total circular loop, for which we have to find the value of �B� at that point. Now, as �dl� is small area of the circle, or we can say it�s a derivative of the total area bounded by the circular loop (circumference of the circular loop), so, if we take an integral of �dl� we can have the total area bounded by the circular loop which is 2pr.  In case of Solenoid: Here, the solenoid has number of turns �N� and is having a

Statistics of ECAT

Given below is the Comparison of the Statistics of ECAT 2015 with the stats of last few years. It clearly indicates that merit is going to fall this year. It might fall as much as 1% or even more.   Marks Interval     Number of Candidates   ECAT 2011      ECAT 2012      ECAT 2013      ECAT 2014      ECAT 2015       Students with marks 0 or Less than 0   408 235 203 248 63 01 - 50 7813 4734 5423 5421 7465 51 - 100 12222 10435 14389 12748 16370 101 - 150 7304 10563 11978 12591 10434 151 - 200 3131 6670 7063 7004 4446 201 - 250 630 2798 2965 2384 1351 251 - 300 43 667 672 488 255 301 - 400 02 114 86 17 41 Total Number of Candidates 31553 36216 42779 40985 40425 Average Marks 96 118 107 107.5 96 The merit this year is going to be lower than the merit of 2012, 2013 & 2014 but will be higher than the merit of 2011. Credits: SWAMI Mianwalli